∛27 × ³log 9 ÷ ²log 4 = ...
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= (3 × 3 × 3)^(1/3) × ³Log 9 ÷ ²Log 4
= 3 × 3Log(3²) ÷ 2Log(2²)
= 3 × 2 ÷ 2
= 6 ÷ 2
= 3
Pembahasan :
³√27 × ³log 9 ÷ ²log 4 =
= ³√3³ × ³log 3² ÷ 2log 2²
= 3 × ( 1 × 2 ) ÷ ( 1 × 2 )
= 3 × 2 ÷ 2
= 6 ÷ 2
= 3
